What is |4(x-1)+10|<= 14 ?

The solution to |4(x-1)+10|<= 14 is -5<= x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|4(x-1)+10|<= 14

∣ 4 (x - 1) + 10 ∣ \leq 14

- 5 \leq x \leq 2

Interval Notation

[- 5, 2]

Solution steps

∣ 4 (x - 1) + 10 ∣ \leq 14

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 14 \leq 4 (x - 1) + 10 \leq 14

4 (x - 1) + 10 \geq - 14 and 4 (x - 1) + 10 \leq 14

x \geq - 5 and x \leq 2

Merge Overlapping Intervals

- 5 \leq x \leq 2

(2^{8})^{\frac{1}{2}}

0 - 4

2 x^{2} + 11 x + 9 = 10 x + 10

11 \geq 3 x - 7 x + 3 - 1

\frac{2 ^{3}}{2 ^{5}}