2^{2x+2}=4^{2x-1}

Lösung

2^{2 x + 2} = 4^{2 x - 1}

x = 2

Schritte zur Lösung

2^{2 x + 2} = 4^{2 x - 1}

Wende Exponentenregel an

2 x + 2 = 2 (2 x - 1)

Löse

2 x + 2 = 2 (2 x - 1) : x = 2

x = 2

9^{n + 1} - 2 \cdot 9^{n} = 7

\frac{8}{3} = 2^{r}

\frac{4 ^{x + 2}}{3 ^{x + 1}} = 16

2^{x} - 1 + 2^{x} + 1 = 2

\frac{1}{8} = \frac{4}{2 ^{\frac{t}{7}}}