erweitern ((2k+1)(k+2))/2

Lösung

erweitern

\frac{( 2 k + 1 ) ( k + 2 )}{2}

k^{2} + \frac{5 k}{2} + 1

Schritte zur Lösung

\frac{( 2 k + 1 ) ( k + 2 )}{2}

Multipliziere aus

(2 k + 1) (k + 2) : 2 k^{2} + 5 k + 2

= \frac{2 k ^{2} + 5 k + 2}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 k ^{2} + 5 k + 2}{2} = \frac{2 k ^{2}}{2} + \frac{5 k}{2} + \frac{2}{2}

= \frac{2 k ^{2}}{2} + \frac{5 k}{2} + \frac{2}{2}

Wende Regel an

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{2 k ^{2}}{2} + \frac{5 k}{2} + 1

Teile die Zahlen:

\frac{2}{2} = 1

= k^{2} + \frac{5 k}{2} + 1

e x p an d \frac{4 ( k + 2 ) ^{2} ( k + 1 )}{3}

\frac{d}{d t} ((x) (6 t^{2} - t^{3}))

\frac{d}{d x} ((y^{3}) c (x - c)^{2})

e x p an d (x^{2} - 2 x - 3)^{5}

e x p an d (8 x - 20) \circ