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受欢迎的代数 >

-2.7t^2+40t+6.5=0

解答

- 2.7 t^{2} + 40 t + 6.5 = 0

解答

t = - \frac{- 200 + 41755}{27}, t = \frac{200 + 41755}{27}

+1

十进制

t = - 0.16075 \dots, t = 14.97557 \dots

求解步骤

- 2.7 t^{2} + 40 t + 6.5 = 0

在两边乘以

10

- 27 t^{2} + 400 t + 65 = 0

使用求根公式求解

t_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 27 ) \cdot 65}{2 ( - 27 )}

40 0^{2} - 4 (- 27) \cdot 65 = 241755

t_{1, 2} = \frac{- 400 \pm 2 41755}{2 ( - 27 )}

将解分隔开

t_{1} = \frac{- 400 + 2 41755}{2 ( - 27 )}, t_{2} = \frac{- 400 - 2 41755}{2 ( - 27 )}

t = \frac{- 400 + 2 41755}{2 ( - 27 )} : - \frac{- 200 + 41755}{27}

t = \frac{- 400 - 2 41755}{2 ( - 27 )} : \frac{200 + 41755}{27}

二次方程组的解是:

t = - \frac{- 200 + 41755}{27}, t = \frac{200 + 41755}{27}

作图

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(18-R)^2+(9-R)^2=R^2

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