solvefor x,x^2+mx+4=0

解

x, x^{2} + m x + 4 = 0

x = \frac{- m + m ^{2} - 16}{2}, x = \frac{- m - m ^{2} - 16}{2}

解答ステップ

x^{2} + m x + 4 = 0

解くとthe二次式

x_{1, 2} = \frac{- m \pm m ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

簡素化

m^{2} - 4 \cdot 1 \cdot 4 : m^{2} - 16

x_{1, 2} = \frac{- m \pm m ^{2} - 16}{2 \cdot 1}

解を分離する

x_{1} = \frac{- m + m ^{2} - 16}{2 \cdot 1}, x_{2} = \frac{- m - m ^{2} - 16}{2 \cdot 1}

x = \frac{- m + m ^{2} - 16}{2 \cdot 1} : \frac{- m + m ^{2} - 16}{2}

x = \frac{- m - m ^{2} - 16}{2 \cdot 1} : \frac{- m - m ^{2} - 16}{2}

二次equationの解:

x = \frac{- m + m ^{2} - 16}{2}, x = \frac{- m - m ^{2} - 16}{2}