2^{1-x}=3^{2x+5}

Lösung

2^{1 - x} = 3^{2 x + 5}

x = - \frac{5 ln ( 3 ) - ln ( 2 )}{ln ( 18 )}

Dezimale

x = - 1.66065 \dots

Schritte zur Lösung

2^{1 - x} = 3^{2 x + 5}

Wende Exponentenregel an

(1 - x) ln (2) = (2 x + 5) ln (3)

Löse

(1 - x) ln (2) = (2 x + 5) ln (3) : x = - \frac{5 ln ( 3 ) - ln ( 2 )}{ln ( 18 )}

x = - \frac{5 ln ( 3 ) - ln ( 2 )}{ln ( 18 )}

e^{2 x - 3} = 75

2^{x^{2} - 2 x + 1} = 1

3 \cdot 2^{x + 2} - 5 \cdot 2^{x} = 56

e^{x + 1} = 3

2 \cdot 1 0^{9 a} = 29