12^x=4^{x+2}

Lösung

1 2^{x} = 4^{x + 2}

x = \frac{4 ln ( 2 )}{ln ( 3 )}

Dezimale

x = 2.52371 \dots

Schritte zur Lösung

1 2^{x} = 4^{x + 2}

Wende Exponentenregel an

x ln (12) = (x + 2) ln (4)

Löse

x ln (12) = (x + 2) ln (4) : x = \frac{4 ln ( 2 )}{ln ( 3 )}

x = \frac{4 ln ( 2 )}{ln ( 3 )}

(\frac{1}{2})^{x} = \frac{1}{16}

78 \cdot 1.05 5^{t} = 110

g (p) = 4^{x}, x = \frac{3}{2}

3 (2^{x}) = 48

2 7^{x} = (\frac{1}{3})^{2 x}