9^{x-2}=(1/3)^{3x-1}

Lösung

9^{x - 2} = (\frac{1}{3})^{3 x - 1}

x = 1

Schritte zur Lösung

9^{x - 2} = (\frac{1}{3})^{3 x - 1}

Wende Exponentenregel an

2 (x - 2) = - (3 x - 1)

Löse

2 (x - 2) = - (3 x - 1) : x = 1

x = 1

9^{x} - 3^{x + 1} = - 2

3^{2 x} = 12

8^{3 x + 1} = 12 8^{x - 2}

7^{x - 4} = 7^{8}

2^{3 - 8 w} = 18