a^x=b,b^y=c,c^z=a

Lösung

a^{x} = b, b^{y} = c, c^{z} = a

x = \frac{ln ( b )}{ln ( a )}

Schritte zur Lösung

a^{x} = b

Wende Exponentenregel an

x ln (a) = ln (b)

Löse

x ln (a) = ln (b) : x = \frac{ln ( b )}{ln ( a )}

x = \frac{ln ( b )}{ln ( a )}

4^{x - 3} = (\frac{1}{8})^{2 x + 1}

6 4^{1 - 2 x} = 0.2 5^{3 x}

4^{1 - x} + 2^{3 - x} - 12 = 0

x = 2^{\frac{x}{2}}

3^{5 x - 1} = 5^{2 x}