2^{2x-1}=4^{3x+2}

Lösung

2^{2 x - 1} = 4^{3 x + 2}

x = - \frac{5}{4}

Dezimale

x = - 1.25

Schritte zur Lösung

2^{2 x - 1} = 4^{3 x + 2}

Wende Exponentenregel an

2 x - 1 = 2 (3 x + 2)

Löse

2 x - 1 = 2 (3 x + 2) : x = - \frac{5}{4}

x = - \frac{5}{4}

7^{(x + 2)} = 98

so l v e f or x, e^{x} - y = 0

1 6^{x + 2} = \frac{1}{4}

(x - 2)^{x^{2} - 2 x} = (x - 2)^{x + 4}

7^{5 x - 4} = 14