36^{x-1}=23^{x+2}

解答

3 \cdot 6^{x - 1} = 2 \cdot 3^{x + 2}

x = \frac{2 ln ( 6 )}{ln ( 2 )}

十进制

x = 5.16992 \dots

求解步骤

3 \cdot 6^{x - 1} = 2 \cdot 3^{x + 2}

使用指数运算法则

ln (3) + (x - 1) ln (6) = ln (2) + (x + 2) ln (3)

解

ln (3) + (x - 1) ln (6) = ln (2) + (x + 2) ln (3) : x = \frac{2 ln ( 6 )}{ln ( 2 )}

x = \frac{2 ln ( 6 )}{ln ( 2 )}

21 6^{x + 4} = (\frac{1}{36})^{x - 1}

C = 100 \cdot 2^{\frac{t}{15}}

5^{x + 2} + 3 \cdot 5^{x + 1} - 8 = 0

0.6 4^{- 5 x + 1} = 0.51 2^{- 5 x + 4}

2 x e^{- x} + (- e^{- x}) x^{2} = 0