5^{x+1}=3^{x+2}

Lösung

5^{x + 1} = 3^{x + 2}

x = \frac{2 ln ( 3 ) - ln ( 5 )}{ln ( 5 ) - ln ( 3 )}

Dezimale

x = 1.15066 \dots

Schritte zur Lösung

5^{x + 1} = 3^{x + 2}

Wende Exponentenregel an

(x + 1) ln (5) = (x + 2) ln (3)

Löse

(x + 1) ln (5) = (x + 2) ln (3) : x = \frac{2 ln ( 3 ) - ln ( 5 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{2 ln ( 3 ) - ln ( 5 )}{ln ( 5 ) - ln ( 3 )}

1 5^{- x + 2} = 1 1^{- 7 x}

9 = 2^{t}

e^{2 x + 3} = 0

e^{2 - 3 x} = 4

3^{x} - 6 (3)^{x} - 27 = 0