10^x=(10^1)(10^{-2})

Lösung

1 0^{x} = (1 0^{1}) (1 0^{- 2})

x = - 1

Schritte zur Lösung

1 0^{x} = (1 0^{1}) (1 0^{- 2})

Wende Exponentenregel an

x = - 1

e^{3} = e^{x + 1}

\frac{1}{8} \cdot 2^{2 x} + 8 = 9

so l v e f or t, 0.2 = e^{- k t}

1 + 3^{z^{2} - 2} = 5

2^{x - 10} = x^{3}