(1+i)(x+iy)=2-5i

解答

(1 + i) (x + i y) = 2 - 5 i

x = - \frac{3}{2}, y = - \frac{7}{2}

求解步骤

(1 + i) (x + i y) = 2 - 5 i

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(1 + i) (x + i y) : (x - y) + i (x + y)

(x - y) + i (x + y) = 2 - 5 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[x - y = 2 x + y = - 5]

[x - y = 2 x + y = - 5] : x = - \frac{3}{2}, y = - \frac{7}{2}

x = - \frac{3}{2}, y = - \frac{7}{2}

\frac{x + i y + 2 + 3 i}{2 x + 2 i y - 3} = i + 2

so l v e f or t, a = v f - \frac{v i}{t}

1.2 x + 3 + y i = 7.2 - 4.3 i

i (x) = 3 x^{2} + 2 x - 1

\frac{18 + i}{4 + 3 i} = a + bi