22(x+yi)+(28+4i)=72-62i

解答

22 (x + y i) + (28 + 4 i) = 72 - 62 i

x = 2, y = - 3

求解步骤

22 (x + y i) + (28 + 4 i) = 72 - 62 i

将

22 (x + y i) + (28 + 4 i)

改写成标准复数形式:

(22 x + 28) + (22 y + 4) i

(22 x + 28) + (22 y + 4) i = 72 - 62 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[22 x + 28 = 72 22 y + 4 = - 62]

[22 x + 28 = 72 22 y + 4 = - 62] : x = 2, y = - 3

x = 2, y = - 3

a x^{2} - b x + 9 + 3 i = 0

2 i (a + bi) + 6 = 9 i + (a + bi)

(x + i y)^{2} = 3 + 2 i

(9 - 7 i) - 7 = x - (7 + y i)

\frac{z}{z + i} = 4