2^{x+3}=5^{2x}

Lösung

2^{x + 3} = 5^{2 x}

x = \frac{3 ln ( 2 )}{2 ln ( 5 ) - ln ( 2 )}

Dezimale

x = 0.82330 \dots

Schritte zur Lösung

2^{x + 3} = 5^{2 x}

Wende Exponentenregel an

(x + 3) ln (2) = 2 x ln (5)

Löse

(x + 3) ln (2) = 2 x ln (5) : x = \frac{3 ln ( 2 )}{2 ln ( 5 ) - ln ( 2 )}

x = \frac{3 ln ( 2 )}{2 ln ( 5 ) - ln ( 2 )}

x^{e} = e^{x}

roo t s a e^{x}

4^{3 x + 1} = 16

3^{2 (x + 1)} - 18 \times 3^{x} + 9 = 0

6^{3 m} \cdot 6^{- m} = 6^{- 2 m}