6^{x+1}=4^{2x-1}

Lösung

6^{x + 1} = 4^{2 x - 1}

x = \frac{ln ( 24 )}{ln ( \frac{8}{3} )}

Dezimale

x = 3.24017 \dots

Schritte zur Lösung

6^{x + 1} = 4^{2 x - 1}

Wende Exponentenregel an

(x + 1) ln (6) = (2 x - 1) ln (4)

Löse

(x + 1) ln (6) = (2 x - 1) ln (4) : x = \frac{ln ( 24 )}{ln ( \frac{8}{3} )}

x = \frac{ln ( 24 )}{ln ( \frac{8}{3} )}

1 - 4 e^{- 4 x} = 0

4^{2 x} = 7

e^{x} x^{2} (x^{2} + x - 6) = 0

so l v e f or t, E^{- 18 t} = \frac{15}{4}

6 (2^{3 x - 1}) - 7 = 9