What are the solutions to the equation 8^2+10^2=x^2 ?

The solutions to the equation 8^2+10^2=x^2 are x=2sqrt(41),x=-2sqrt(41)

Find the zeros of 8^2+10^2=x^2

The zeros of 8^2+10^2=x^2 are x=2sqrt(41),x=-2sqrt(41)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8^{2} + 1 0^{2} = x^{2}

x = 241, x = - 241

Solution steps

8^{2} + 1 0^{2} = x^{2}

Switch sides

x^{2} = 8^{2} + 1 0^{2}

Simplify

8^{2} + 1 0^{2} : 164

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 164, x = - 164

164 = 241

- 164 = - 241

x = 241, x = - 241

2 x^{2} + 7 x - 2 = - x^{2} + 2 x

2 (3 x + 1) + 3 x - 2 + x = 2 (4 x - 5) + 2 (2 x - 3)

lo g_{8} (4096)

3 x^{2} + 4 = 13 x

- x (x - 5) (x + 4) > 0

What are the solutions to the equation 8^2+10^2=x^2 ?
The solutions to the equation 8^2+10^2=x^2 are x=2sqrt(41),x=-2sqrt(41)
Find the zeros of 8^2+10^2=x^2
The zeros of 8^2+10^2=x^2 are x=2sqrt(41),x=-2sqrt(41)