2x^2+10x-4=0

解答

2 x^{2} + 10 x - 4 = 0

x = \frac{- 5 + 33}{2}, x = - \frac{5 + 33}{2}

十进制

x = 0.37228 \dots, x = - 5.37228 \dots

求解步骤

2 x^{2} + 10 x - 4 = 0

使用求根公式求解

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 4) = 233

x_{1, 2} = \frac{- 10 \pm 2 33}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- 10 + 2 33}{2 \cdot 2}, x_{2} = \frac{- 10 - 2 33}{2 \cdot 2}

x = \frac{- 10 + 2 33}{2 \cdot 2} : \frac{- 5 + 33}{2}

x = \frac{- 10 - 2 33}{2 \cdot 2} : - \frac{5 + 33}{2}

二次方程组的解是:

x = \frac{- 5 + 33}{2}, x = - \frac{5 + 33}{2}

s im pl i f y \frac{- 8 x ^{4} y}{24 x ^{9} y ^{8}}

f a c t or e^{u} - (u - 1) \cdot e^{u}

f a c t or m^{2} n^{2} + m n^{2} - 2 m^{2} n

(\frac{1}{N} + \frac{0.0004}{1 - 0.0004 N}) d N = d t

x^{2} - 10 x + 24 > 0