integral from 0 to pi/3 of tan^3(x)

Lösung

\int_{0}^{\frac{π}{3}} tan^{3} (x) d x

- ln (2) + \frac{3}{2}

Dezimale

0.80685 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{3}} tan^{3} (x) d x

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= \int_{0}^{\frac{π}{3}} (- 1 + sec^{2} (x)) tan (x) d x

Wende U-Substitution an

= \int_{1}^{2} \frac{- 1 + u ^{2}}{u} d u

Multipliziere aus

\frac{- 1 + u ^{2}}{u} : - \frac{1}{u} + u

= \int_{1}^{2} - \frac{1}{u} + u d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{2} \frac{1}{u} d u + \int_{1}^{2} u d u

\int_{1}^{2} \frac{1}{u} d u = ln (2)

\int_{1}^{2} u d u = \frac{3}{2}

= - ln (2) + \frac{3}{2}

\int (cos (x))^{3} d x

x^{^{''}} + 8 x^{^{'}} + 16 x = 0

\frac{d}{d x} (5 x - 8)

t a y l or X^{\frac{9}{6}}, 7

\frac{d}{d x} (tan (3^{x}))