What is (d^2)/(dx^2)((3x-2)/(2x+1)) ?

The answer to (d^2)/(dx^2)((3x-2)/(2x+1)) is -(28)/((2x+1)^3)

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(d^2)/(dx^2)((3x-2)/(2x+1))

\frac{d ^{2}}{d x ^{2}} (\frac{3 x - 2}{2 x + 1})

- \frac{28}{( 2 x + 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{3 x - 2}{2 x + 1})

\frac{d}{d x} (\frac{3 x - 2}{2 x + 1}) = \frac{7}{( 2 x + 1 ) ^{2}}

= \frac{d}{d x} (\frac{7}{( 2 x + 1 ) ^{2}})

\frac{d}{d x} (\frac{7}{( 2 x + 1 ) ^{2}}) = - \frac{28}{( 2 x + 1 ) ^{3}}

= - \frac{28}{( 2 x + 1 ) ^{3}}

\frac{d}{d x} (\frac{lo g _{3} ( x )}{lo g _{7} ( x )})

\int x^{2} - cos (x) d x

d x + e^{5 x} d y = 0

s^{2} + 2 s + 1

y = x^{2} e^{x} - 2 x e^{x} + 4 e^{x}

What is (d^2)/(dx^2)((3x-2)/(2x+1)) ?
The answer to (d^2)/(dx^2)((3x-2)/(2x+1)) is -(28)/((2x+1)^3)