What is derivative of f(x)=-16t^2 ?

The answer to derivative of f(x)=-16t^2 is (dt)/(dx)=0

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derivative of f(x)=-16t^2

derivative of

f (x) = - 16 t^{2}

\frac{d t}{d x} = 0

Solution steps

f (x) = - 16 t^{2}

Treat

t

t (x)

Differentiate both sides:

0 = - 32 t \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{s - 1}{2 ( s ^{2} + 1 )}

2 x^{2} - 5 x + 3

sin (x - x^{2})

\frac{d}{d x} (2^{2^{x}})

\int tan^{2} (3 x) sec^{2} (3 x) d x

What is derivative of f(x)=-16t^2 ?
The answer to derivative of f(x)=-16t^2 is (dt)/(dx)=0