What is the tangent of 2x^2-5x+3 ?

The tangent of 2x^2-5x+3 is y=(4a_{0}-5)x-2a_{0}^2+3

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tangent of 2x^2-5x+3

tangent of

2 x^{2} - 5 x + 3

y = (4 a_{0} - 5) x - 2 a_{0}^{2} + 3

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} - 5 a_{0} + 3)

Find the slope of

y = 2 x^{2} - 5 x + 3 : \frac{d y}{d x} = 4 x - 5

Compute the slope of

y = 2 x^{2} - 5 x + 3

x = a_{0} : m = 4 a_{0} - 5

Find the line with slope m=

4 a_{0} - 5

and passing through

(a_{0}, 2 a_{0}^{2} - 5 a_{0} + 3) : y = (4 a_{0} - 5) x - 2 a_{0}^{2} + 3

y = (4 a_{0} - 5) x - 2 a_{0}^{2} + 3

sin (x - x^{2})

\frac{d}{d x} (2^{2^{x}})

\int tan^{2} (3 x) sec^{2} (3 x) d x

\int - \frac{cos ( x )}{sin ^{2} ( x )} d x

\int \frac{3}{x} + 10 x - 3 d x

What is the tangent of 2x^2-5x+3 ?
The tangent of 2x^2-5x+3 is y=(4a_{0}-5)x-2a_{0}^2+3