What is (\partial)/(\partial x)(cos(x+y+z)) ?

The answer to (\partial)/(\partial x)(cos(x+y+z)) is -sin(x+y+z)

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(\partial)/(\partial x)(cos(x+y+z))

\frac{\partial}{\partial x} (cos (x + y + z))

- sin (x + y + z)

Solution steps

\frac{\partial}{\partial x} (cos (x + y + z))

Treat

y, z

as constants

Apply the chain rule:

- sin (x + y + z) \frac{\partial}{\partial x} (x + y + z)

= - sin (x + y + z) \frac{\partial}{\partial x} (x + y + z)

\frac{\partial}{\partial x} (x + y + z) = 1

= - sin (x + y + z) \cdot 1

Simplify

= - sin (x + y + z)

k = 1 \sum \infty \frac{2}{3} (1.5)^{k - 1}

f (x) = cos (3 x^{2})

\frac{x}{x + 7}

y^{^{'}} = \frac{3 x ^{2} 16 + y ^{2}}{y}

\frac{d}{d t} (t e^{3 t})

What is (\partial)/(\partial x)(cos(x+y+z)) ?
The answer to (\partial)/(\partial x)(cos(x+y+z)) is -sin(x+y+z)