What is the tangent of y=x^2-2,(-3,7) ?

The tangent of y=x^2-2,(-3,7) is y=-6x-11

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tangent of y=x^2-2,(-3,7)

tangent of

y = x^{2} - 2, (- 3, 7)

y = - 6 x - 11

Solution steps

Find the slope of

y = x^{2} - 2 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} - 2

(- 3, 7) : m = - 6

Find the line with slope m=

- 6

and passing through

(- 3, 7) : y = - 6 x - 11

y = - 6 x - 11

3 x y^{^{'}} = y^{2} - y - 2

f (x) = ln (3 x)

\int \frac{1}{( 4 - x ^{2} )} d x

\int (1 - x)^{\frac{1}{2}} d x

\int 9 x (9 - x^{- 4}) d x

What is the tangent of y=x^2-2,(-3,7) ?
The tangent of y=x^2-2,(-3,7) is y=-6x-11