inverselaplace 3/((s-2)^2)

Lösung

inverse laplace transformation

\frac{3}{( s - 2 ) ^{2}}

e^{2 t} \cdot 3 t

Schritte zur Lösung

L^{- 1} {\frac{3}{( s - 2 ) ^{2}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {F (s - a)} = e^{a t} f (t)

Für

\frac{3}{( s - 2 ) ^{2}} : a = 2, F (s) = \frac{3}{s ^{2}}

= e^{2 t} L^{- 1} {\frac{3}{s ^{2}}}

L^{- 1} {\frac{3}{s ^{2}}} : 3 t

= e^{2 t} \cdot 3 t

\frac{\partial}{\partial x} (arctan (7 x t))

\int \frac{sin ( θ )}{θ} d θ

\int \frac{3 e ^{2 x}}{e ^{2 x} + 13 e ^{x} + 40} d x

x \to 0 lim (- x^{2} + 3 x + a)

\frac{d h}{d t} = 0.3 (5 - h)