What is the solution for (dy)/(dx)=e^{2x+5y} ?

The solution for (dy)/(dx)=e^{2x+5y} is y=-(ln(-5/2 e^{2x}-c_{1}))/5

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(dy)/(dx)=e^{2x+5y}

\frac{d y}{d x} = e^{2 x + 5 y}

y = - \frac{ln ( - \frac{5}{2} e ^{2 x} - c _{1} )}{5}

Solution steps

\frac{d y}{d x} = e^{2 x + 5 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{5}{2} e ^{2 x} - c _{1} )}{5}

y = - \frac{ln ( - \frac{5}{2} e ^{2 x} - c _{1} )}{5}

\frac{d}{d x} (\frac{x ^{2} - 9 x + 7}{x ^{2} + 9})

10 tan^{2} (6 x)

\frac{d}{d x} (2 sin (2 x) - 4 sin^{9} (2 x))

\frac{d}{d x} (x^{\frac{2}{3}} (5 - x))

19 - x^{2}, - 2 x + 16, - 5, - 19

What is the solution for (dy)/(dx)=e^{2x+5y} ?
The solution for (dy)/(dx)=e^{2x+5y} is y=-(ln(-5/2 e^{2x}-c_{1}))/5