(dy)/(dx)=6-3x^2

Lösung

\frac{d y}{d x} = 6 - 3 x^{2}

y = 6 x - x^{3} + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = 6 - 3 x^{2}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = 6 - 3 x^{2}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 6 - 3 x^{2} d x

\int 6 - 3 x^{2} d x = 6 x - x^{3} + c_{1}

y = 6 x - x^{3} + c_{1}

\int e^{x} \cdot x^{- 1} d x

\frac{d y}{d x} = \frac{4 y ln ( x )}{x}

\int_{\frac{π}{2}}^{π} 2 cot (\frac{x}{2}) d x

f (x) = \frac{x cos ( x ) - sin ( x )}{x ^{2}}

x \to - 3 - lim (\frac{1}{( x + 3 ) ^{4}})