What is the derivative of k^x+x^k ?

The derivative of k^x+x^k is k^xln(k)+kx^{k-1}

What is the first derivative of k^x+x^k ?

The first derivative of k^x+x^k is k^xln(k)+kx^{k-1}

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\frac{d}{d x} (k^{x} + x^{k})

k^{x} ln (k) + k x^{k - 1}

Solution steps

\frac{d}{d x} (k^{x} + x^{k})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (k^{x}) + \frac{d}{d x} (x^{k})

\frac{d}{d x} (k^{x}) = k^{x} ln (k)

\frac{d}{d x} (x^{k}) = k x^{k - 1}

= k^{x} ln (k) + k x^{k - 1}

\int_{0}^{2} 2 π (x + 1) (12 - 6 x) d x

g (x) = 3^{(\frac{x}{2})}

x \to 2 lim (\frac{( 3 )}{x - 2})

\int sec^{7} (3 x) tan (3 x) d x

x \to 0 - lim (cot (x))

What is the derivative of k^x+x^k ?
The derivative of k^x+x^k is k^xln(k)+kx^{k-1}
What is the first derivative of k^x+x^k ?
The first derivative of k^x+x^k is k^xln(k)+kx^{k-1}