xy^'+y=e^x,y(1)=6

Lösung

x y^{^{'}} + y = e^{x}, y (1) = 6

y = \frac{e ^{x}}{x} + \frac{6 - e}{x}

Schritte zur Lösung

x y^{'} (x) + y = e^{x}

Solve linear ODE:

y = \frac{e ^{x}}{x} + \frac{6 - e}{x}

y = \frac{e ^{x}}{x} + \frac{6 - e}{x}

\int \frac{9}{6 + 9 x} d x

\int (2^{x} + e^{π}) d x

d er i v a t i v e e^{7}

d x + e^{3} x d y = 0

t an g e n t f (x) = x^{2}, (- 1, - 3)