What is the derivative of y=x^2+2x-2 ?

The derivative of y=x^2+2x-2 is 2x+2

What is the first derivative of y=x^2+2x-2 ?

The first derivative of y=x^2+2x-2 is 2x+2

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derivative of

y = x^{2} + 2 x - 2

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

y^{^{'}} = e^{9 y - x}

f (x) = x^{3}, at x = - 5

x \to 0 lim (1 - cos (3 x))

x \to \infty lim (lo g_{2} (lo g_{2} (x) - 1))

\int_{0}^{\frac{π}{2}} sin^{5} (x) d x

What is the derivative of y=x^2+2x-2 ?
The derivative of y=x^2+2x-2 is 2x+2
What is the first derivative of y=x^2+2x-2 ?
The first derivative of y=x^2+2x-2 is 2x+2