What is the derivative of (x^5-2x/(-5)) ?

The derivative of (x^5-2x/(-5)) is -x^4+2/5

What is the first derivative of (x^5-2x/(-5)) ?

The first derivative of (x^5-2x/(-5)) is -x^4+2/5

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\frac{d}{d x} (\frac{x ^{5} - 2 x}{- 5})

- x^{4} + \frac{2}{5}

Solution steps

\frac{d}{d x} (\frac{x ^{5} - 2 x}{- 5})

Simplify

\frac{x ^{5} - 2 x}{- 5} : - \frac{x ^{5} - 2 x}{5}

= \frac{d}{d x} (- \frac{x ^{5} - 2 x}{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{5} \frac{d}{d x} (x^{5} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{1}{5} (\frac{d}{d x} (x^{5}) - \frac{d}{d x} (2 x))

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (2 x) = 2

= - \frac{1}{5} (5 x^{4} - 2)

Simplify

- \frac{1}{5} (5 x^{4} - 2) : - x^{4} + \frac{2}{5}

= - x^{4} + \frac{2}{5}

7 u^{e}

e^{- x^{2}}

\int \frac{2 x}{( x ^{2} + 1 ) ^{2}} d x

\int_{\frac{π}{6}}^{\frac{π}{4}} cos (x) d x

s (t) = 5^{t}

What is the derivative of (x^5-2x/(-5)) ?
The derivative of (x^5-2x/(-5)) is -x^4+2/5
What is the first derivative of (x^5-2x/(-5)) ?
The first derivative of (x^5-2x/(-5)) is -x^4+2/5