What is the derivative of \sqrt[3]{x}+2sqrt(x^3) ?

The derivative of \sqrt[3]{x}+2sqrt(x^3) is 1/(3x^{2/3)}+3sqrt(x)

What is the first derivative of \sqrt[3]{x}+2sqrt(x^3) ?

The first derivative of \sqrt[3]{x}+2sqrt(x^3) is 1/(3x^{2/3)}+3sqrt(x)

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derivative of

\frac{1}{3 x ^{\frac{2}{3}}} + 3 x

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (2 x^{3}) = 3 x

= \frac{1}{3 x ^{\frac{2}{3}}} + 3 x

\int \frac{1}{3 x - x ^{2}} d x

5 \frac{d x}{d t} + 10 x = 120 sin (60 t)

f (x) = \frac{1}{x - 2}, at x = 6

\int \frac{1}{2 sin ( x ) - cos ( x ) + 5} d x

\frac{d}{d x} ((5)^{x})

What is the derivative of \sqrt[3]{x}+2sqrt(x^3) ?
The derivative of \sqrt[3]{x}+2sqrt(x^3) is 1/(3x^{2/3)}+3sqrt(x)
What is the first derivative of \sqrt[3]{x}+2sqrt(x^3) ?
The first derivative of \sqrt[3]{x}+2sqrt(x^3) is 1/(3x^{2/3)}+3sqrt(x)