What is the derivative of f(x)=(x+3)^2 ?

The derivative of f(x)=(x+3)^2 is 2(x+3)

What is the first derivative of f(x)=(x+3)^2 ?

The first derivative of f(x)=(x+3)^2 is 2(x+3)

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derivative of

f (x) = (x + 3)^{2}

2 (x + 3)

Solution steps

\frac{d}{d x} ((x + 3)^{2})

Apply the chain rule:

2 (x + 3) \frac{d}{d x} (x + 3)

= 2 (x + 3) \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= 2 (x + 3) \cdot 1

Simplify

= 2 (x + 3)

\int_{\frac{1}{2}}^{1} (x^{- 3} - 2) d x

y = 6 x e^{x}, (0, 0)

cos (4 t)

\frac{\partial}{\partial x} (e^{- y} (x + e^{y}))

y = x^{2}, y = 2

What is the derivative of f(x)=(x+3)^2 ?
The derivative of f(x)=(x+3)^2 is 2(x+3)
What is the first derivative of f(x)=(x+3)^2 ?
The first derivative of f(x)=(x+3)^2 is 2(x+3)