y^{-2}(dy)/(dx)+y^{-1}=2x

Lösung

y^{- 2} \frac{d y}{d x} + y^{- 1} = 2 x

y = \frac{1}{2 x + 2 + c _{1} e ^{x}}

Schritte zur Lösung

y^{- 2} \frac{d y}{d x} + y^{- 1} = 2 x

Solve Bernoulli ODE:

y = \frac{1}{2 x + 2 + c _{1} e ^{x}}

y = \frac{1}{2 x + 2 + c _{1} e ^{x}}

\frac{\partial}{\partial x} (e^{3 x} tan (y))

y^{^{''}} + 6 y^{^{'}} - 16 y = 0

\frac{\partial}{\partial x} (ln (tan (x)))

x \to - 5 - lim (\frac{( - 7 x )}{x + 5})

\int \frac{1}{x ^{3} + 3 x ^{2} + 7 x + 5} d x