What is the derivative of (4x^2+3^2) ?

The derivative of (4x^2+3^2) is 16x(4x^2+3)

What is the first derivative of (4x^2+3^2) ?

The first derivative of (4x^2+3^2) is 16x(4x^2+3)

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\frac{d}{d x} ((4 x^{2} + 3)^{2})

16 x (4 x^{2} + 3)

Solution steps

\frac{d}{d x} ((4 x^{2} + 3)^{2})

Apply the chain rule:

2 (4 x^{2} + 3) \frac{d}{d x} (4 x^{2} + 3)

= 2 (4 x^{2} + 3) \frac{d}{d x} (4 x^{2} + 3)

\frac{d}{d x} (4 x^{2} + 3) = 8 x

= 2 (4 x^{2} + 3) \cdot 8 x

Simplify

= 16 x (4 x^{2} + 3)

y = x (x^{4} + 1)

\int_{0}^{1} arcsin (w) d w

x \to 0 + lim (x^{x})

\frac{d}{d x} (arcsin (1 - x^{2}))

y = 2, y = sin (x), x = 0, x = π

What is the derivative of (4x^2+3^2) ?
The derivative of (4x^2+3^2) is 16x(4x^2+3)
What is the first derivative of (4x^2+3^2) ?
The first derivative of (4x^2+3^2) is 16x(4x^2+3)