What is the derivative of-2x^2-5 ?

The derivative of-2x^2-5 is -4x

What is the first derivative of-2x^2-5 ?

The first derivative of-2x^2-5 is -4x

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\frac{d}{d x} (- 2 x^{2} - 5)

- 4 x

Solution steps

\frac{d}{d x} (- 2 x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5) = 0

= - 4 x - 0

Simplify

= - 4 x

y = x^{2} - 2, y = 2

2 x^{2} + y^{2} = 9

5 t^{2} ln (t)

e^{x}, e^{- 4 x}, ln (3)

f (x) = 7 e^{x} + x