What is the solution for 7yy^'=x ?

The solution for 7yy^'=x is y=sqrt((x^2+c_{1))/7},y=-sqrt((x^2+c_{1))/7}

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7yy^'=x

7 y y^{^{'}} = x

y = \frac{x ^{2} + c _{1}}{7}, y = - \frac{x ^{2} + c _{1}}{7}

Solution steps

7 y y^{'} (x) = x

Solve separable ODE:

y = \frac{x ^{2} + c _{1}}{7}, y = - \frac{x ^{2} + c _{1}}{7}

y = \frac{x ^{2} + c _{1}}{7}, y = - \frac{x ^{2} + c _{1}}{7}

x \to (a + 1) lim (x^{2} - 1)

\frac{d}{d x} (\frac{3}{2} x)

cos (3 t - 1)

y^{^{''}} + 7 y^{^{'}} + 10 y = - 11 t e^{2 t}

\int (4 x + 1)^{3} d x

What is the solution for 7yy^'=x ?
The solution for 7yy^'=x is y=sqrt((x^2+c_{1))/7},y=-sqrt((x^2+c_{1))/7}