What is laplacetransform cos(3t-1) ?

The answer to laplacetransform cos(3t-1) is (cos(1)s+3sin(1))/(s^2+9)

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laplacetransform cos(3t-1)

laplace transform

cos (3 t - 1)

\frac{cos ( 1 ) s + 3 sin ( 1 )}{s ^{2} + 9}

Solution steps

L {cos (3 t - 1)}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (3 t - 1)} = \frac{s cos ( - 1 ) - 3 sin ( - 1 )}{s ^{2} + 3 ^{2}}

= \frac{s cos ( - 1 ) - 3 sin ( - 1 )}{s ^{2} + 3 ^{2}}

= \frac{cos ( 1 ) s + 3 sin ( 1 )}{s ^{2} + 9}

y^{^{''}} + 7 y^{^{'}} + 10 y = - 11 t e^{2 t}

\int (4 x + 1)^{3} d x

- sec (\frac{1}{x} + 7 x)

\frac{d}{d x} (x e^{- 2 x^{2}})

\frac{\partial}{\partial x} (7 e^{x y})

What is laplacetransform cos(3t-1) ?
The answer to laplacetransform cos(3t-1) is (cos(1)s+3sin(1))/(s^2+9)