What is the derivative of \sqrt[3]{x}tan(5x) ?

The derivative of \sqrt[3]{x}tan(5x) is (tan(5x))/(3x^{2/3)}+5\sqrt[3]{x}sec^2(5x)

What is the first derivative of \sqrt[3]{x}tan(5x) ?

The first derivative of \sqrt[3]{x}tan(5x) is (tan(5x))/(3x^{2/3)}+5\sqrt[3]{x}sec^2(5x)

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Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (tan (5 x)) = sec^{2} (5 x) \cdot 5

\frac{1}{3 x ^{\frac{2}{3}}} tan (5 x) = \frac{tan ( 5 x )}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (\frac{x}{ln ( x )})

4 t (\frac{d y}{d t}) - y = t

\int \frac{1}{144 + x ^{2}} d x

sin (3 x) + cos (4 x)

What is the derivative of \sqrt[3]{x}tan(5x) ?
The derivative of \sqrt[3]{x}tan(5x) is (tan(5x))/(3x^{2/3)}+5\sqrt[3]{x}sec^2(5x)
What is the first derivative of \sqrt[3]{x}tan(5x) ?
The first derivative of \sqrt[3]{x}tan(5x) is (tan(5x))/(3x^{2/3)}+5\sqrt[3]{x}sec^2(5x)