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Popular Calculus >

y^'=(2y)/x-x^2y^2

Solution

y^{^{'}} = \frac{2 y}{x} - x^{2} y^{2}

Solution

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

Solution steps

y^{'} (x) = \frac{2 y}{x} - x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(2y)/x-x^2y^2 ?
The solution for y^'=(2y)/x-x^2y^2 is y=(5x^2)/(x^5+c_{1)}