What is the derivative of f(x)=2x^3+4x^2+6x ?

The derivative of f(x)=2x^3+4x^2+6x is 6x^2+8x+6

What is the first derivative of f(x)=2x^3+4x^2+6x ?

The first derivative of f(x)=2x^3+4x^2+6x is 6x^2+8x+6

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derivative of

f (x) = 2 x^{3} + 4 x^{2} + 6 x

6 x^{2} + 8 x + 6

Solution steps

\frac{d}{d x} (2 x^{3} + 4 x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (6 x) = 6

= 6 x^{2} + 8 x + 6

x \to 0 + lim (sin (\frac{5 π}{6} e^{x}))

\int (x + 1) [ln (x + 1) + c] d x

y^{2} y^{^{'}} = y^{2}

f (x) = x^{2} - 2 x

\int \frac{x ^{3}}{x ^{2} + 9} d x

What is the derivative of f(x)=2x^3+4x^2+6x ?
The derivative of f(x)=2x^3+4x^2+6x is 6x^2+8x+6
What is the first derivative of f(x)=2x^3+4x^2+6x ?
The first derivative of f(x)=2x^3+4x^2+6x is 6x^2+8x+6