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Popular >

derivative of f(x)=19xe^x

Solution

derivative of

f (x) = 19 x e^{x}

Solution

19 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (19 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 19 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 19 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 19 (1 \cdot e^{x} + e^{x} x)

Simplify

= 19 (e^{x} + e^{x} x)

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\int x^{2} cos (\frac{1}{9} x) d x

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\frac{\partial}{\partial x} (\frac{x ^{2} - y}{x ^{2} + y})

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\int \frac{8 cosh ( x )}{x} d x

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=19xe^x ?
The derivative of f(x)=19xe^x is 19(e^x+e^xx)
What is the first derivative of f(x)=19xe^x ?
The first derivative of f(x)=19xe^x is 19(e^x+e^xx)