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人気のある微分積分 >

limit as x approaches infinity of \sqrt[4]{n}*(sqrt(n+3))/(2n+1)

解

x \to \infty lim (4 n \cdot \frac{n + 3}{2 n + 1})

解

4 n \frac{n + 3}{2 n + 1}

解答ステップ

x \to \infty lim (4 n \frac{n + 3}{2 n + 1})

x \to a lim c = c

= 4 n \frac{n + 3}{2 n + 1}

グラフ

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