derivative of (3x-1^4*(2x+1)^{-3})

Lösung

\frac{d}{d x} ((3 x - 1)^{4} \cdot (2 x + 1)^{- 3})

\frac{12 ( 3 x - 1 ) ^{3}}{( 2 x + 1 ) ^{3}} - \frac{6 ( 3 x - 1 ) ^{4}}{( 2 x + 1 ) ^{4}}

Schritte zur Lösung

\frac{d}{d x} ((3 x - 1)^{4} (2 x + 1)^{- 3})

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (3 x - 1)^{4}, g = (2 x + 1)^{- 3}

= \frac{d}{d x} ((3 x - 1)^{4}) (2 x + 1)^{- 3} + \frac{d}{d x} ((2 x + 1)^{- 3}) (3 x - 1)^{4}

\frac{d}{d x} ((3 x - 1)^{4}) = 12 (3 x - 1)^{3}

\frac{d}{d x} ((2 x + 1)^{- 3}) = - \frac{6}{( 2 x + 1 ) ^{4}}

= 12 (3 x - 1)^{3} (2 x + 1)^{- 3} + (- \frac{6}{( 2 x + 1 ) ^{4}}) (3 x - 1)^{4}

Vereinfache

12 (3 x - 1)^{3} (2 x + 1)^{- 3} + (- \frac{6}{( 2 x + 1 ) ^{4}}) (3 x - 1)^{4} : \frac{12 ( 3 x - 1 ) ^{3}}{( 2 x + 1 ) ^{3}} - \frac{6 ( 3 x - 1 ) ^{4}}{( 2 x + 1 ) ^{4}}

= \frac{12 ( 3 x - 1 ) ^{3}}{( 2 x + 1 ) ^{3}} - \frac{6 ( 3 x - 1 ) ^{4}}{( 2 x + 1 ) ^{4}}

x \to 1 lim (\frac{5 - 5 x}{1 - x})

n = 0 \sum \infty n^{n} a^{n}

\int x^{\frac{1}{3}} sin (x^{\frac{4}{3}} - 8) d x

\frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2}}{2 x})

\frac{d}{d x} (5 - 4 x^{2})