derivative f(x)=(5x-7)/(6x-9)

Lösung

ableitung von

f (x) = \frac{5 x - 7}{6 x - 9}

- \frac{1}{3 ( 2 x - 3 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{5 x - 7}{6 x - 9})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 5 x - 7 ) ( 6 x - 9 ) - \frac{d}{d x} ( 6 x - 9 ) ( 5 x - 7 )}{( 6 x - 9 ) ^{2}}

\frac{d}{d x} (5 x - 7) = 5

\frac{d}{d x} (6 x - 9) = 6

= \frac{5 ( 6 x - 9 ) - 6 ( 5 x - 7 )}{( 6 x - 9 ) ^{2}}

Vereinfache

\frac{5 ( 6 x - 9 ) - 6 ( 5 x - 7 )}{( 6 x - 9 ) ^{2}} : - \frac{1}{3 ( 2 x - 3 ) ^{2}}

= - \frac{1}{3 ( 2 x - 3 ) ^{2}}

\int x e^{t x} d x

\frac{d}{d x} (\frac{- 12 x}{( x ^{2} + 3 ) ^{2}})

d er i v a t i v e 2 x^{2} - 6 x + 3

\int_{2}^{3} \frac{27}{3 - x} d x

n = 2 \sum \infty e^{3 - 6 n}