derivative of 3/(2x+7)

Lösung

\frac{d}{d x} (\frac{3}{2 x + 7})

- \frac{6}{( 2 x + 7 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{3}{2 x + 7})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{2 x + 7})

Wende Exponentenregel an:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((2 x + 7)^{- 1})

Wende die Kettenregel an:

- \frac{1}{( 2 x + 7 ) ^{2}} \frac{d}{d x} (2 x + 7)

= - \frac{1}{( 2 x + 7 ) ^{2}} \frac{d}{d x} (2 x + 7)

\frac{d}{d x} (2 x + 7) = 2

= 3 (- \frac{1}{( 2 x + 7 ) ^{2}} \cdot 2)

Vereinfache

3 (- \frac{1}{( 2 x + 7 ) ^{2}} \cdot 2) : - \frac{6}{( 2 x + 7 ) ^{2}}

= - \frac{6}{( 2 x + 7 ) ^{2}}

\int_{- 2}^{2} \frac{10}{x ^{2} - 2 x - 24} d x

f (x) = 1 - 2 cos (x)

\int cot (\frac{x}{9}) d x

d er i v a t i v e \frac{x}{( x ^{2} + 3 x ) ^{5}}

x \to \infty lim (x n (x))