(\partial)/(\partial y)(e^{x^2+y^2})

Lösung

\frac{\partial}{\partial y} (e^{x^{2} + y^{2}})

e^{x^{2} + y^{2}} \cdot 2 y

Schritte zur Lösung

\frac{\partial}{\partial y} (e^{x^{2} + y^{2}})

Behandle

x

als Konstante

Wende die Kettenregel an:

e^{x^{2} + y^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

= e^{x^{2} + y^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

\frac{\partial}{\partial y} (x^{2} + y^{2}) = 2 y

= e^{x^{2} + y^{2}} \cdot 2 y

k = 1 \sum \infty e^{- k}

\frac{\partial}{\partial x} (4 x y arcsin (yz))

\int \frac{8}{9 t 81 t ^{2} - 64} d t

\int (\frac{tan ( x )}{cot ( x )})^{3} d x

\frac{\partial}{\partial x} (y e^{y} - x e^{x})