What is the derivative of-2x^2+3x-4 ?

The derivative of-2x^2+3x-4 is -4x+3

What is the first derivative of-2x^2+3x-4 ?

The first derivative of-2x^2+3x-4 is -4x+3

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\frac{d}{d x} (- 2 x^{2} + 3 x - 4)

- 4 x + 3

Solution steps

\frac{d}{d x} (- 2 x^{2} + 3 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= - 4 x + 3 - 0

Simplify

= - 4 x + 3

\frac{d y}{d x} = \frac{3 y}{x}, x > 0

\int \frac{3}{x ln ( x )} d x

\frac{d}{d x} (\frac{x ^{3}}{39} + \frac{13}{4 x})

f (x) = \frac{2}{t ^{3}}

\frac{d ^{2} y}{d x ^{2}}, x^{2} + y^{2} = 16

What is the derivative of-2x^2+3x-4 ?
The derivative of-2x^2+3x-4 is -4x+3
What is the first derivative of-2x^2+3x-4 ?
The first derivative of-2x^2+3x-4 is -4x+3