What is derivative of f(x)= 2/(t^3) ?

The answer to derivative of f(x)= 2/(t^3) is (dt)/(dx)=0

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derivative of f(x)= 2/(t^3)

derivative of

f (x) = \frac{2}{t ^{3}}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{2}{t ^{3}}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{6 \frac{d t}{d x}}{t ^{4}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d ^{2} y}{d x ^{2}}, x^{2} + y^{2} = 16

\frac{\partial}{\partial z} (x y + yz - x z)

1 - y^{2} d x = 1 - x^{2} d y

\int_{0}^{2} \frac{2 x}{( x ^{2} + 5 ) ^{3}} d x

x \to 0 lim (\frac{- 2 e ^{- x}}{2 x - 2})

What is derivative of f(x)= 2/(t^3) ?
The answer to derivative of f(x)= 2/(t^3) is (dt)/(dx)=0